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watchdog: it87_wdt: don't print out if registering watchdog fails

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The core will do this already.

Signed-off-by: Wolfram Sang <wsa+renesas@sang-engineering.com>
Reviewed-by: Guenter Roeck <linux@roeck-us.net>
Link: https://lore.kernel.org/r/20241004200314.5459-6-wsa+renesas@sang-engineering.com
Signed-off-by: Guenter Roeck <linux@roeck-us.net>
Signed-off-by: Wim Van Sebroeck <wim@linux-watchdog.org>
This commit is contained in:
Wolfram Sang 2024-10-04 22:03:08 +02:00 committed by Wim Van Sebroeck
parent fb2de4ea05
commit ebc75304f0
1 changed files with 1 additions and 3 deletions
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4
drivers/watchdog/it87_wdt.c
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@ -349,10 +349,8 @@ static int __init it87_wdt_init(void)
watchdog_stop_on_reboot(&wdt_dev);
rc = watchdog_register_device(&wdt_dev);
if (rc) {
pr_err("Cannot register watchdog device (err=%d)\n", rc);
if (rc)
return rc;
}
pr_info("Chip IT%04x revision %d initialized. timeout=%d sec (nowayout=%d testmode=%d)\n",
chip_type, chip_rev, timeout, nowayout, testmode);