fs/ntfs3: fix potential double iput on d_make_root() failure

d_make_root() consumes the reference to the passed inode: it either
attaches it to the newly created dentry on success, or drops it via
iput() on failure.

In the error path, the code currently does:
    sb->s_root = d_make_root(inode);
    if (!sb->s_root)
        goto put_inode_out;

which leads to a second iput(inode) in put_inode_out. This results in
a double iput and may trigger a use-after-free if the inode gets freed
after the first iput().

Fix this by jumping directly to the common cleanup path, avoiding the
extra iput(inode).

Signed-off-by: Zhan Xusheng <zhanxusheng@xiaomi.com>
Signed-off-by: Konstantin Komarov <almaz.alexandrovich@paragon-software.com>
This commit is contained in:
Zhan Xusheng 2026-03-26 17:12:32 +08:00 committed by Konstantin Komarov
parent 984a415f01
commit d1062683bf
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@ -1704,7 +1704,7 @@ static int ntfs_fill_super(struct super_block *sb, struct fs_context *fc)
sb->s_root = d_make_root(inode);
if (!sb->s_root) {
err = -ENOMEM;
goto put_inode_out;
goto out;
}
if (boot2) {