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x86: Rely on generic printing of preemption model
After __die_header(), __die_body() is always invoked. There we have show_regs() -> show_regs_print_info() which prints the current preemption model. Remove it from the initial line. Signed-off-by: Sebastian Andrzej Siewior <bigeasy@linutronix.de> Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org> Link: https://lore.kernel.org/r/20250314160810.2373416-8-bigeasy@linutronix.de
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@ -395,18 +395,13 @@ NOKPROBE_SYMBOL(oops_end);
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static void __die_header(const char *str, struct pt_regs *regs, long err)
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{
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const char *pr = "";
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/* Save the regs of the first oops for the executive summary later. */
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if (!die_counter)
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exec_summary_regs = *regs;
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if (IS_ENABLED(CONFIG_PREEMPTION))
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pr = IS_ENABLED(CONFIG_PREEMPT_RT) ? " PREEMPT_RT" : " PREEMPT";
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printk(KERN_DEFAULT
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"Oops: %s: %04lx [#%d]%s%s%s%s%s\n", str, err & 0xffff,
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++die_counter, pr,
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"Oops: %s: %04lx [#%d]%s%s%s%s\n", str, err & 0xffff,
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++die_counter,
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IS_ENABLED(CONFIG_SMP) ? " SMP" : "",
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debug_pagealloc_enabled() ? " DEBUG_PAGEALLOC" : "",
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IS_ENABLED(CONFIG_KASAN) ? " KASAN" : "",
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