x86: Rely on generic printing of preemption model

After __die_header(), __die_body() is always invoked. There we have
show_regs() -> show_regs_print_info() which prints the current
preemption model.
Remove it from the initial line.

Signed-off-by: Sebastian Andrzej Siewior <bigeasy@linutronix.de>
Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org>
Link: https://lore.kernel.org/r/20250314160810.2373416-8-bigeasy@linutronix.de
This commit is contained in:
Sebastian Andrzej Siewior 2025-03-14 17:08:08 +01:00 committed by Peter Zijlstra
parent b70f50be0c
commit 96389cf365

View File

@ -395,18 +395,13 @@ NOKPROBE_SYMBOL(oops_end);
static void __die_header(const char *str, struct pt_regs *regs, long err)
{
const char *pr = "";
/* Save the regs of the first oops for the executive summary later. */
if (!die_counter)
exec_summary_regs = *regs;
if (IS_ENABLED(CONFIG_PREEMPTION))
pr = IS_ENABLED(CONFIG_PREEMPT_RT) ? " PREEMPT_RT" : " PREEMPT";
printk(KERN_DEFAULT
"Oops: %s: %04lx [#%d]%s%s%s%s%s\n", str, err & 0xffff,
++die_counter, pr,
"Oops: %s: %04lx [#%d]%s%s%s%s\n", str, err & 0xffff,
++die_counter,
IS_ENABLED(CONFIG_SMP) ? " SMP" : "",
debug_pagealloc_enabled() ? " DEBUG_PAGEALLOC" : "",
IS_ENABLED(CONFIG_KASAN) ? " KASAN" : "",