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btrfs: return block group directly at btrfs_next_block_group()

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At btrfs_next_block_group(), we have this long line with two statements:

  cache = btrfs_lookup_first_block_group(...); return cache;

This makes it a bit harder to read due to two statements on the same
line, so change that to directly return the result of the call to
btrfs_lookup_first_block_group().

Reviewed-by: Nikolay Borisov <nborisov@suse.com>
Signed-off-by: Filipe Manana <fdmanana@suse.com>
Reviewed-by: David Sterba <dsterba@suse.com>
Signed-off-by: David Sterba <dsterba@suse.com>
This commit is contained in:
Filipe Manana 2022-04-13 16:20:42 +01:00 committed by David Sterba
parent 16b0c2581e
commit 8b01f931c1
1 changed files with 1 additions and 1 deletions
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2
fs/btrfs/block-group.c
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@ -271,7 +271,7 @@ struct btrfs_block_group *btrfs_next_block_group(
read_unlock(&fs_info->block_group_cache_lock);
btrfs_put_block_group(cache);
cache = btrfs_lookup_first_block_group(fs_info, next_bytenr); return cache;
return btrfs_lookup_first_block_group(fs_info, next_bytenr);
}
node = rb_next(&cache->cache_node);
btrfs_put_block_group(cache);