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btrfs: don't call btrfs_handle_fs_error() in btrfs_commit_transaction()
There's no need to call btrfs_handle_fs_error() as we are inside a transaction and if we get an error we jump to the 'scrub_continue' label and end up calling cleanup_transaction(), which aborts the transaction. This is odd given that we have a transaction handle and that in the transaction commit path any error makes us abort the transaction and it's the only place that calls btrfs_handle_fs_error(). Remove the btrfs_handle_fs_error() call and replace it with an error message so that if it happens we know what went wrong during the transaction commit. Also annotate the condition in the if statement with 'unlikely' since this is not expected to happen. We've been wanting to remove btrfs_handle_fs_error(), so this removes one user that does not even needs it. Reviewed-by: Johannes Thumshirn <johannes.thumshirn@wdc.com> Signed-off-by: Filipe Manana <fdmanana@suse.com> Reviewed-by: David Sterba <dsterba@suse.com> Signed-off-by: David Sterba <dsterba@suse.com>
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@ -2550,9 +2550,8 @@ int btrfs_commit_transaction(struct btrfs_trans_handle *trans)
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wake_up_process(fs_info->cleaner_kthread);
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ret = btrfs_write_and_wait_transaction(trans);
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if (ret) {
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btrfs_handle_fs_error(fs_info, ret,
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"Error while writing out transaction");
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if (unlikely(ret)) {
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btrfs_err(fs_info, "error while writing out transaction: %d", ret);
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mutex_unlock(&fs_info->tree_log_mutex);
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goto scrub_continue;
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}
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