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x86/fpu: Shift fpregs_assert_state_consistent() from arch_exit_work() to its caller
If CONFIG_X86_DEBUG_FPU=Y, arch_exit_to_user_mode_prepare() calls arch_exit_work() even if ti_work == 0. There only reason is that we want to call fpregs_assert_state_consistent() if TIF_NEED_FPU_LOAD is not set. This looks confusing. arch_exit_to_user_mode_prepare() can just call fpregs_assert_state_consistent() unconditionally, it depends on CONFIG_X86_DEBUG_FPU and checks TIF_NEED_FPU_LOAD itself. Signed-off-by: Oleg Nesterov <oleg@redhat.com> Signed-off-by: Ingo Molnar <mingo@kernel.org> Cc: Chang S . Bae <chang.seok.bae@intel.com> Cc: H. Peter Anvin <hpa@zytor.com> Cc: Andy Lutomirski <luto@amacapital.net> Cc: Brian Gerst <brgerst@gmail.com> Cc: Linus Torvalds <torvalds@linux-foundation.org> Cc: Peter Zijlstra <peterz@infradead.org> Link: https://lore.kernel.org/r/20250503143902.GA9012@redhat.com
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@ -53,7 +53,6 @@ static inline void arch_exit_work(unsigned long ti_work)
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if (unlikely(ti_work & _TIF_IO_BITMAP))
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tss_update_io_bitmap();
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fpregs_assert_state_consistent();
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if (unlikely(ti_work & _TIF_NEED_FPU_LOAD))
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switch_fpu_return();
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}
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@ -61,7 +60,9 @@ static inline void arch_exit_work(unsigned long ti_work)
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static inline void arch_exit_to_user_mode_prepare(struct pt_regs *regs,
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unsigned long ti_work)
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{
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if (IS_ENABLED(CONFIG_X86_DEBUG_FPU) || unlikely(ti_work))
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fpregs_assert_state_consistent();
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if (unlikely(ti_work))
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arch_exit_work(ti_work);
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fred_update_rsp0();
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