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drm/amd/display: fix math_mod() using arg1 instead of arg2
[Why] math_mod() multiplied by arg1 instead of arg2, returning a wrong result for any non-trivial modulo operation. [How] Replace arg1 with arg2 in the subtraction term to correctly implement fmod(arg1, arg2). Cc: Mario Limonciello <mario.limonciello@amd.com> Cc: Alex Deucher <alexander.deucher@amd.com> Cc: stable@vger.kernel.org Reviewed-by: Dillon Varone <dillon.varone@amd.com> Signed-off-by: Wenjing Liu <wenjing.liu@amd.com> Signed-off-by: Aurabindo Pillai <aurabindo.pillai@amd.com> Tested-by: Dan Wheeler <daniel.wheeler@amd.com> Signed-off-by: Alex Deucher <alexander.deucher@amd.com>
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@ -23,7 +23,7 @@ double math_mod(const double arg1, const double arg2)
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return arg2;
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if (isNaN(arg2))
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return arg1;
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return arg1 - arg1 * ((int)(arg1 / arg2));
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return arg1 - arg2 * ((int)(arg1 / arg2));
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}
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double math_min2(const double arg1, const double arg2)
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